Partial Differential Equation Assignment Help
1. A climate scientist makes the following observations on the weather in Ballarat in winter:
i There are never two consecutive days of nice weather.
ii Following a nice day, there are equal probabilities (i.e. 1) of having either a rainy day or a windy day.
iii Following a rainy day or a windy day, the probability of having the same weather the next day is 1, and the probability of having a nice day is 1.
a) What is the state space of this process?
b) Write down the Markov chain modelling the weather in Ballarat according to these ob-servations.
c) Show that this is a regular Markov chain.
d) Find the equilibrium (stationary) distribution of the Markov chain.
e) In the 3 months (90 days) of winter, how many days of nice weather can be expected? 1+1+2+2+1 marks
2. Let u(x, t) be a function of two variables which satisfies the following partial differential equation:
N u - + - = 3x Ox x
a) Solve to determine u. (Note that the PDE contains only u, derivatives of u, and functions of x.
b) Find the solution which satisfies u(1, t) = sin2 t. c) Find any non-constant solution to the following partial differential equation: 02u 1 Ou 0 Ox0y x Oy
3. Rewrite the third-order differential equation cos tym(t) + sy (t) - ety(t) = 2t as a system of first-order differential equation.
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1)
a) State space for this process is shown below :
State Space = {nice day, rainy day, windy day}
b)
The Markov chain Modeling of the weather in Ballarat according to these observations is shown below :
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C)
So to show regular markov matrix it should be P2=P.
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Therefore As Matrix multiplication gives P so it is a regular markov matrix.
d)
The equilibrium distribution of the markov chain is as below :
S =[ 1/2 1/4 1/4 ]
Since,
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Therefore as P * S gives S itself So it is equilibrium distribution.
e)
Total number of observations of days in weather = 90 days
Now,
Probability = favorable observations/ total number of observations
Probability of nice days = 1/4
So
1/4 = number of expected nice days/90
number of expected nice days = 1/4*90 = 22.5
So the numbers of expected nice days are 23 days.
2)
The differential equation given :
du/dx + u/x = 3x
a)
?u/?x + u/x = 3*x
Multiplying x with whole equation on both sides gives
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Integrating both sides
u*x = 3*x3/3
So the answer is u = x2 .
b)
Now putting U(1,t) in the above solution u = x2 gives as
As U(1,t) = sin2t
1 = sin2t
t = 90o , -90o
c)
Given :
?2u/?x?y + (1/x) *?u/?y = 0
Now rearranging the equation
- ?2u/?x?y = (1/x) *?u/?y
Integrating on both sides with respect to x and then with y we get
u = - (log x)*y
3)
given:
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Y = AX
x1 = x
x’1 = x2
x’2 = x3
x’3 = x4
x’4 = (2*x1 + et *x1 – * x2)/
So the third order differential equation is written as a system of first order differential equation as :
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